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Hello Samuel,<br>
<br>
Currently, parser ... lexer, in fact, try to read "number" and
convert it to floating point number, at this moment, we have no idea
what the final goal of this number.<br>
After that, the parser try to understand what to do with this number
(already a double).<br>
So I think the first case is not possible with the current
management of numbers.<br>
<br>
For string argument, I think it cannot be done easily in an overload
macro for the same reason.<br>
But it can be done in (u)int builtin .<br>
<br>
Regards,<br>
Antoine<br>
<div class="moz-cite-prefix">Le 27/10/2018 à 01:06, Samuel Gougeon a
écrit :<br>
</div>
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cite="mid:def34a2e-5f00-cbd6-bb89-1f9d12dd9bea@free.fr">
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<p>Hello,</p>
<p>Here is an awkward case. I am afraid that it won't be possible
to improve the situation, but let's see it:</p>
<tt>--> int64(461168601842738791)</tt><tt><br>
</tt>
<p><tt> ans =</tt><tt><br>
</tt><tt> 461168601842738816 <<< ..38816 =/= ..38791</tt><tt><br>
</tt><font face="Arial"><br>
</font>I know that this comes from the fact that the literal <tt>461168601842738791</tt>
is <i>by default </i>parsed as the decimal number <tt>461168601842738791.</tt>,
and since <tt>1/461168601842738791 < %eps</tt>, there is a
round-off error, after what the "truncated" decimal number is
converted into an int64.<br>
<br>
So, the question is: in the specific cases of int64() and
uint64(), would it be possible to parse literals input arguments
assuming that they are not decimal?</p>
<p>Before parsing the literal, could the parser be aware that the
calling function is int64() or uint64()?</p>
<p>Another solution -- may be easier to implement -- to provide
literal numbers to int64() and uint64() without rounding them
could be to support string inputs, as for instance hex2dec()
does it. It is presently not the case, and the overloading is
not enabled:</p>
<p><tt>--> int64("</tt><tt><tt>461168601842738791</tt>")<br>
int64: Wrong type for input argument #1: integer, boolean or
double expected.</tt></p>
Samuel
<p><br>
</p>
<br>
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