negative poly-exponents
Alexander Bluem
A.Bluem at fhtw-berlin.de
Fri May 23 14:36:00 CEST 2008
hello,
I am trying to design discrete filters using the z-transform.
At my university we are doing so in this form:
H(z) = ( (z - z_01) * (z - z_02) ) / ( (z - z_x1) * (z - z_x2) )
of course the result is with positive z-exponents. now: how do I get the
representation with negative exponents ?
for example:
zo=1.25;
zx=0.8;
z=poly(0,'z');
(z-zo)/(z-zx)
ans =
- 1.25 + z
--------
- 0.8 + z
but I'd like this output:
-1
1 - 1.25z
--------
-1
1 - 0.8z
any hints are much appreciated.
Alex
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