Passing arguments by reference

[André FS]

Hello, people.

Is there any special operator to do that?

-->function f(x)
-->   (?)x = (?)x+1
-->endfunction;
-->a=1;
-->f(a);
-->disp(a);
   2

--
André FS
Aeronautical Engineering Student
Instituto Tecnológico de Aeronáutica (www.ita.br)
CENIC (http://www.cenic.biz/index_1.html)