[scilab-Users] false results in Rosenbrock equation

Michaël Baudin michael.baudin at scilab.org
Tue Jan 18 09:21:48 CET 2011


Your test case allowed me to a bug with respect to the management of the 
output function in the case of Box's algorithm. I reported it at :

http://bugzilla.scilab.org/show_bug.cgi?id=8805

Regards,

Michaël

Le 18/01/2011 09:19, Michaël Baudin a écrit :
> Hi Paul,
>
> The status of the optimization is not good when the parameters are 
> left to the default values :
>
> -->neldermead_get(nm,"-status")
>  ans =
> maxfuneval
>
> This means that the maximum number of function evaluations where 
> reached before the convergence was attained. All we need to do is to 
> increase the maximum number of function evaluations. In order to get 
> even closer to the optimum, we must also increase the number of 
> iterations.
>
> nm = neldermead_configure(nm,"-maxfunevals",200);
> nm = neldermead_configure(nm,"-maxiter",200);
>
> Once done, I get :
>
> -->xopt = neldermead_get(nm,"-xopt")
>  xopt  =
>     1.0035954
>     1.0073491
>
> This is quite a difficult case for Nelder-Mead's algorithm. The 
> simplex has to go through a long curved valley before reaching the 
> zone where the function begins to behave as a quadratic function.
>
> Rosenbrock's function has only one global minimum, at x=[1,1]. The 
> point x=[-1,1] is not a minimum.
>
> This is easy to check with Scilab. First, let us define the function.
>
>     function [f,G,H] = rosenbrock(x)
>         f = 100*(x(2) - x(1)^2)^2 + (1 - x(1))^2;
>
>         // Calculation of the gradient G vector
>         G(1) = -400*x(1)*(x(2) - x(1)^2) - 2*(1 - x(1));
>         G(2) = 200*(x(2) - x(1)^2);
>
>         // Calculation of the Hessian matrix
>         H(1,1) = -400*x(2) + 1200*x(1)^2 + 2;
>         H(1,2) = -400*x(1);
>         H(2,1) = -400*x(1);
>         H(2,2) = 200;
>     endfunction
>
> We get at x= [1,1] :
>
> -->[f,G,H] = rosenbrock([1,1])
>  H  =
>     802.  - 400.
>   - 400.    200.
>  G  =
>     0.
>     0.
>  f  =
>     0.
>
> This means that the gradient is zero, implying that the first order 
> conditions for unconstrained optimality are satisfied. Moreover, the 
> eigenvalues of the Hessian matrix are positive, as shown below :
>
> -->spec(H)
>  ans  =
>     0.3993608
>     1001.6006
>
> This implies that the local curvature of the Rosenbrock function is 
> positive : x* is indeed a minimum.
>
> Now, at x=[-1,1], we get :
>
> -->[f,G,H] = rosenbrock([-1,1])
>  H  =
>     802.    400.
>     400.    200.
>  G  =
>   - 4.
>     0.
>  f  =
>     4.
>
> The gradient is nonzero, which means that the first order optimality 
> conditions are not satisfied at x=[-1,1]. Rosenbrock's function is a 
> sum of squares.
>
> Best regards,
>
> Michaël
>
>
> Le 17/01/2011 11:18, Carrico, Paul a écrit :
>> Dear all
>> In the Rosenbrock equation it is well known the 2 minima are (1,1) 
>> and (-1,1) ; in the attached where I want to test several 
>> optimization macros (and basic &particular functions) I've a 
>> different result as descibed herebellow : is there a mistake in the 
>> input file or does something go wrong ?
>> Please note the functions inputs are as general as possible to be 
>> used with the different macros (fminsearch, optim and so on)
>> Paul
>> #################################################################"
>>     - X1 optimized = 0.229978
>>     - X2 optimized = 0.0240434
>> --------------------------------------------------------------------------------
>>
>>
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>
>
> -- 
> Michaël Baudin
> Ingénieur de développement
> michael.baudin at scilab.org
> -------------------------
> Consortium Scilab - Digiteo
> Domaine de Voluceau - Rocquencourt
> B.P. 105 - 78153 Le Chesnay Cedex
> Tel. : 01 39 63 56 87 - Fax : 01 39 63 55 94
>


-- 
Michaël Baudin
Ingénieur de développement
michael.baudin at scilab.org
-------------------------
Consortium Scilab - Digiteo
Domaine de Voluceau - Rocquencourt
B.P. 105 - 78153 Le Chesnay Cedex
Tel. : 01 39 63 56 87 - Fax : 01 39 63 55 94


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