[scilab-Users] Drawing Y-axis in graph

Sumit Adhikari sumit.adhikari at gmail.com
Sat Jun 25 21:13:55 CEST 2011


Seems a good time for you to migrate to newer versions of scilab

Regards,
-- 
Sumit Adhikari,
Institute of Computer Technology,
Faculty of Electrical Engineering,
Vienna University of Technology,
Gußhausstraße 27-29,1040 Vienna

On Sat, Jun 25, 2011 at 9:09 PM, Sumit Adhikari <sumit.adhikari at gmail.com>wrote:

> That is what I see! Please check the attached pdf file for what I see
> Regards,
>
>
> --
> Sumit Adhikari,
> Institute of Computer Technology,
> Faculty of Electrical Engineering,
> Vienna University of Technology,
> Gußhausstraße 27-29,1040 Vienna
>
>
>
> On Sat, Jun 25, 2011 at 9:04 PM, Prof. Dr. Reinaldo Golmia Dante <
> tiraduvidascefet at yahoo.com> wrote:
>
>> Hi Sumit,
>>
>> Do you see Y-axis at x = 0 ?
>>
>> I don't see it ...
>>
>> Regards,
>> Reinaldo.
>>
>> *From:* Sumit Adhikari <sumit.adhikari at gmail.com>
>> *To:* users at lists.scilab.org
>> *Sent:* Saturday, June 25, 2011 3:18 PM
>> *Subject:* Re: [scilab-Users] Drawing Y-axis in graph
>>
>>
>> But I see Y-axis in your plot on my scilab!
>>
>> Regards,
>> --
>> Sumit Adhikari,
>> Institute of Computer Technology,
>> Faculty of Electrical Engineering,
>> Vienna University of Technology,
>> Gußhausstraße 27-29,1040 Vienna
>>
>>
>> On Sat, Jun 25, 2011 at 8:01 PM, Prof. Dr. Reinaldo Golmia Dante <
>> tiraduvidascefet at yahoo.com> wrote:
>>
>> Dear Scilab users,
>>
>> I would like to draw Y-axis in a graph, but it does not display !
>>
>> See the Scilab-codes:
>>
>>
>> function f=funcao(x)f = 2*x*exp(-x^2);   endfunction
>> x_inicial = -4x_final = 4xdata = linspace ( x_inicial , x_final, 100);
>> y_inicial = -1.0;y_final = 1.0;
>> plot (xdata, funcao)xtitle ( "Função" , "X axis " , "Y axis " );drawaxis(x=x_inicial:x_final,y=0,dir='d',tics='v'); //Here X-axis displaysdrawaxis(y=y_inicial:y_final,x=0,dir='d',tics='v'); // I try to do the same, but Y-axis does not display  :-(((legend ( "2*x*exp(-x^2)" );
>>
>> I appreciate your comments.
>>
>> Thank you in advance.
>>
>> All best,
>>
>> Reinaldo.
>>
>>
>>
>>
>>
>>
>>
>
>
>
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