[scilab-Users] Datevec Problem in scilab

[Mike Page]

Hi,

AFAIK, datenum uses the integer part for the date and the fractional part
for the time.  There are rounding errors and limited precision which make
your result very slightly inaccurate.  datevec gives the number of seconds
as a fraction, so if you are sure your values are all whole numbers of
seconds, you can do some rounding like:

-->int(datevec(datenum(2010,4,6,1,0,0) + (0.5/24/60/60)))
 ans  =

    2010.    4.    6.    1.    0.    0.

But if your times have fractions of a second, then you can never represent
them to infinite precision...

HTH,
Mike.


-----Original Message-----
From: gourish [mailto:gourish2k at gmail.com]
Sent: 19 March 2012 08:41
To: users at lists.scilab.org
Subject: [scilab-Users] Datevec Problem in scilab


hi,

i had run the following instruction in scilab

"*datevec(datenum(2010,4,6,1,0,0))*"
which gives the result as "*ans = 2010. 4. 6. 0. 59. 59.999997*" instead of
"*ans = 2010. 4. 6. 1. 0. 0.*"

is there any solution for the problem?

Thanks,
Gourish


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