[scilab-Users] Question about Scilab

[Mike Page]

You could do something like:

-->p=poly([24 -50 35 -10 1],'x','coeff')
 p  =

                  2     3   4
    24 - 50x + 35x - 10x + x

-->roots(p)
 ans  =

    4.
    3.
    2.
    1.

HTH,
Mike.


-----Original Message-----
From: Andrea Lapiccirella [mailto:andrea.lapiccirella at cnr.it]
Sent: 30 May 2012 15:02
To: users at lists.scilab.org
Subject: [scilab-Users] Question about Scilab


To whom it concerns,
I am entirely new to SCILAB and I would like to know if it is possible to
solve a quartic equation of an unknown.
I do know the coefficients of the different powers of the above quoted
unknown.
Thanks

Dottor Andrea Lapiccirella
Via Francesco Marconi, 6
00168 Roma
Cell +39 328 5710190

No virus found in this message.
Checked by AVG - www.avg.com
Version: 2012.0.2178 / Virus Database: 2425/5032 - Release Date: 05/29/12