[Scilab-users] Vectorization : how to proceed

[Paul Carrico]

Finally I think I’ve found how to proceed .. at the same time I think I
understood the use of the dot “.” (see after the cos)

 

Paul

 

###################################################

function vect_fct=fct_angles(i, j)

    vect_fct3 = [ (cos(i). * sin(j) ) (-sin(j)) i j];

endfunction

 

B = zeros(130321,4);

theta_vect = (0:360)'.*.ones(361,1);

fi_vect = (ones(361,1)'.*.[0:360])';

 

B = fct_angles3(theta_vect([1:130321],1),fi_vect([1:130321],1));

 

 

 

 

De : users-bounces at lists.scilab.org [mailto:users-bounces at lists.scilab.org]
De la part de Paul Carrico
Envoyé : mardi 20 novembre 2012 14:34
À : 'International users mailing list for Scilab.'
Objet : [Scilab-users] Vectorization : how to proceed

 

Dear All

 

In the above example, how can I proceed to perform the product (see function
fct_angles2) ?

 

Indeed, theta are 2 vectors, so no problem for the fct_angles 
 but in case
of product, it’s naturally not work !!! what is the correct syntax in order
to use vectorization ?

 

Thanks 

 

Paul

 

######################################################

mode(0)

 

    function vect_fct=fct_angles(i, j)

        vect_fct = [cos(i)+sin(j) -sin(j) i j];

    endfunction

 

    function vect_fct2=fct_angles2(i, j)

        vect_fct = [cos(i)*sin(j) -sin(j) i j];

    endfunction

    

    

    B1 = zeros(130321,4);

    theta_vect = (0:360)'.*.ones(361,1);

    fi_vect = (ones(361,1)'.*.[0:360])';

    

    B1 = fct_angles(theta_vect([1:130321],1),fi_vect([1:130321],1));

    B2 = fct_angles2(theta_vect([1:130321],1),fi_vect([1:130321],1));

 

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