[Scilab-users] discrete Fourier transform

[haasejos]

hello,
for signalanalysis I would like to use discrete Fourier transform (dft). To
see, how it works, I use the simple example below. Why is *XfA =
abs(Xf)*2/n* respectively why is  XfA = abs(Xf) wrong?

clear; clc; xdel;

function y = f(x);
    y = sin(x);
endfunction;
n = 200;    
x=linspace(0,2*%pi,n);
y=f(x);

mat = [x',y'];
//disp(mat);
//plot2d(x , y);

//xtitle('DATA','n''','y''');  

Xf=dft(y,-1);
XfA = abs(Xf)*2/n;  
plot2d3([1:n/2]',XfA(1:n/2));




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