[Scilab-users] discrete Fourier transform
haasejos
haasejos at web.de
Thu Mar 21 20:34:28 CET 2013
good evening,
what I meant is, that XfA(2) should be "1". Because this value can be
understood as the amplitude of sin(x). But XfA(2) beeing calculated with
XfA=abs(Xf) (see example) returns "100". This is wrong, isn't it?
Josef
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