[Scilab-users] Advice from Scilab community

[CHEZE David 227480]

Hi Paul,

You may have a look at the function find() which is a serialized function and then you may test the size of the result which will tell you if there's a match and where.
At first sight you'll have to test sequentially with the 4 different permutations (only 4 iterations).

David

De : users [mailto:users-bounces at lists.scilab.org] De la part de Carrico, Paul
Envoyé : mardi 22 octobre 2013 13:58
À : users at lists.scilab.org
Objet : [Scilab-users] Advice from Scilab community

Dear All

I'm asking here an advice from the community in order to find a (fast and clean) solution ; I've the following issue :

-          I've a (n x 4) matrix where n may be huge (several hundred thousand of lines is common )

-          I need to find and to remove the line wich has the same numbers (but different in order)

-          I know that there's only one occurrence ... thus when it has been found, not necessary to continue

Example :

A = [
X  X  X      X
X  X  X      X
1 9 1000 994423
X  X  X      X
X  X  X      X
X  X  X      X
1000 994423 1 9  ... or 994423 1 9 1000 ... or 9 1000 994423 ... only 3 possible permutations
X  X  X      X
X  X  X      X
X  X  X      X
]

Any suggestion that avoids the use of (intensive ugly) loops ?


NB:
additional question :

-          If t = [1 2 3 4]

-          If v = [1 2 3 4]

-          If z = [0 2 3 9]

-          Then (t == v) provides [T T T T]

-          Then (z == v) provides [F T T F]

-           .... Is it possible to have a single Boolean with all the cells met the requirement (T) and when it's not the case (F) ?

Thanks in advance

Paul



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