[Scilab-users] Advice from Scilab community

[Stefan Du Rietz]

You can use vectorfind() three times to get the line number.

Regards
Stefan.



On 2013-10-22 13:58, Carrico, Paul wrote:
--------------------
> Dear All
>
> I’m asking here an advice from the community in order to find a (fast
> and clean) solution ; I’ve the following issue :
>
> -I’ve a (n x 4) matrix where n may be huge (several hundred thousand
> of lines is common )
>
> -I need to find and to remove the line wich has the same numbers (but
> different in order)
>
> -I know that there’s only one occurrence … thus when it has been
> found, not necessary to continue
>
> Example :
>
> A = [
>
> X  X  X      X
>
> X  X  X      X
>
> 1 9 1000 994423
>
> X  X  X      X
>
> X  X  X      X
>
> X  X  X      X
>
> 1000 994423 1 9  … or 994423 1 9 1000 … or 9 1000 994423 … only 3
> possible permutations
>
> X  X  X      X
>
> X  X  X      X
>
> X  X  X      X
>
> ]
>
> Any suggestion that avoids the use of (intensive ugly) loops ?
>
> NB:
>
> additional question :
>
> -If t = [1 2 3 4]
>
> -If v = [1 2 3 4]
>
> -If z = [0 2 3 9]
>
> -Then (t == v) provides [T T T T]
>
> -Then (z == v) provides [F T T F]
>
> -…. Is it possible to have a single Boolean with all the cells met the
> requirement (T) and when it’s not the case (F) ?
>
> Thanks in advance
>
> Paul
>
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