[Scilab-users] qustion on functional argument

[Samuel Gougeon]

Hello fugimoto2005,

You may use find():
b = x
k = find(x>1)
b(k) = x(k)+1

Just do the same to process the second case.

Regards
samuelgougeon2015

Le 19/04/2015 17:57, fujimoto2005 a écrit :
> I define a function with a scalar argument and use it with a matrix argument.
> I want to get the matrix whose entry is the functional value for each entry
> of a matrix argument.
> When the function contains no "if then" close, I get the desired result as
> the following function "f".
> However when the function contains "if then "close, the function returns the
> inverse matrix as the following function "g".
> It is because "x>1" is false as a matrix and “else part” is executed as
> inverse matrix calculation.
> I want to get the code that "if then" is applied for each entry of matrix.
> Please teach how to get such a code.
>
> **code****
> function a=f(x)
>      a=x+1
> endfunction
> X=[1,2;3,4]
> f(X)
>
> function b=g(x)    if x>1 then
>          b=x+1
>      else
>          b=1/x
>      end
> endfunction
> X=[1,2;0.1,-0.1]
> g(X)//returns inverse(X)
>
>
>
>
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