[Scilab-users] Help to understand XCOS

[Eddie Liberato]

Thanks Dr. Cordero, that's the explanation I was looking for.

Eddie

On Thu, Oct 8, 2015 at 1:29 PM, Cordero R. <rcorderog at gmail.com> wrote:

> Hi
> The integration function is correct. The problem is not the initial point.
> But the integral of a sinusoidal function is not just a 90 degrees out of
> phase. It will be clear if you consider a definite integral from 0 to t:
>
>   t                               t                  0
> Ssin(x) dx = -cos(x)|  = cos(x)|  = cos(0) - cos(t) = 1 - cos(t)
>  0                               0                 t
>
> For that reason, there is an offset in the result of the integration.
>
> Att
> Dr. Raymundo Cordero G.
>
>
> 2015-10-05 4:08 GMT-04:00 Clément David <
> clement.david at scilab-enterprises.com>:
>
>> Hello eddie,
>>
>> See http://math2.org/math/integrals/more/restrig.htm
>>
>> In fact you can move the starting point by changing the '1/s' initial
>> value (which is by default 0).
>>
>> Regards,
>>
>> --
>> Clément
>>
>> Le samedi 03 octobre 2015 à 09:49 -0700, eddie Liberato a écrit :
>> > Hi,
>> >
>> > Going straight to the point, I don't understand why Xcos mess with
>> > the
>> > amplitude when integrating the sine function. It shouldn't only go
>> > 90° out
>> > of phase?
>> > Someone can point where is my mistake ?
>> > thanks in advance.
>> >
>> > <http://mailinglists.scilab.org/file/n4032956/54.png>
>> >
>> >
>> >
>> > --
>> > View this message in context:
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