[Scilab-users] 'fsolver'

[Serge Steer]

May be you can  use optim instead of fsolve using f(x)^2+alpha*norm(x)^2 
as cost function with alpha small enough
If you cannot compute the gradient of the cost function  you can use the 
numderivative function to estimate it.
Serge
Le 27/01/2016 16:54, fujimoto2005 a écrit :
> The feature of my f(x) defined for x>0 is as follows.
> f(x)<0 for x<x1
> f(x1)=0
> f(x) >0 for x1<x<x2
> f(x)=0 for x>=x2
>
> 'fsolver' gives some x such as x>x2 as a solution.
> I want to get x1 as a solution.
>
>
>
>
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