[Scilab-users] [EXTERNAL] !--error 21
Jens Simon Strom
j.s.strom at hslmg.de
Thu Oct 6 11:45:50 CEST 2016
Hallo Frieder,
insert the line
disp('################'), c=c,sizeA=size(A)
before the problem line
if A(c-1,3)==0 then
and you will see what happens there.
Regards
Jens
-----------------------------------
Am 06.10.2016 08:29, schrieb Frieder Nikolaisen:
> With the real Code, it's more difficult to predict the first c.
>
> Thats why I do use
>> //start of buggy code
>> if c>=2 then...
> to make sure, that c=1 cant Trouble the following code.
>
>
> Am 06.10.2016 08:21, schrieb Carrico, Paul:
>> Without launching the code, I would say :
>> C = 1 : 30
>> And
>> A(c-1,3)
>>
>> If c = 1 then A(0,3) that is not possible since the index start to 1
>> ... no ?
>>
>>
>> -----Message d'origine-----
>> De : users [mailto:users-bounces at lists.scilab.org] De la part de
>> Frieder Nikolaisen Envoyé : jeudi 6 octobre 2016 08:18 À : Users
>> mailing list for Scilab Objet : [EXTERNAL] [Scilab-users] !--error 21
>>
>> Hello everybody,
>>
>> I do have a code, I cannot find the mistake. I get the error:
>>
>> " if A(c-1,3)==0 then
>> !--error 21
>> ungültiger Index.
>> at line 11 of exec file called by :
>> exec('M:\CAD\Abteilungen\Praktikanten\Nikolaisen,
>> Frieder\Fahrdaten\Testprogramm\Archive\test2.sce', -1)"
>>
>> My minimal example Code with random Matrix instead of the real used
>> one:
>>
>> //example code
>>
>> for c=1:10
>> A=rand(10:30)
>> dm=0
>> vor_starter=0
>> starter=0
>>
>> //start of buggy code
>> if c>=2 then
>> if A(c-1,3)==0 then
>> if A(c,7)>0 then
>> beginnZ=c
>> vor_starter=1 /
>> end
>> end
>> //Endzeile festlegen
>> if vor_starter==1 then
>> if A(c-1,7)>0 then /
>> if A(c,7)<=0 then
>> endZ=c-1
>> starter=1
>> vor_starter=0
>> end
>> end
>> end
>>
>> //Berechnung der Zugmasse
>> if starter==1 then
>> time3=datevec(A(beginnZ,1))
>> time4=datevec(A(endZ,1))
>> delta_t=etime(time3, time4)
>> delta_v=(A(endZ,3)-A(beginnZ,3)*3.6) // m/s
>> length_F=length(beginnZ:endZ)
>> mittel_F=sum(A(beginnz:endZ,6)/length_F)
>> dm= (delta_t/delta_v) / mittel_F
>> starter=0
>> end
>> end
>>
>> if dm~=0 then
>> disp(dm)
>> end
>>
>> // end of buggy code
>>
>> end
>>
>>
>>
>> The real Matrix Looks like These:
>> Zeit Distanz Geschwindigkeit 1 Drehzahl
>> Getriebeausgangsleistung
>> [Watt] Zugkraft [N] Beschleunigung [m/s^2] Cv-Druck
>> Richtung Lokbremse
>> anlegen Lokbremse lösen Zugbremse anlegen Zugbremse lösen
>> Kupplung
>> betätigt Bremsen aktiv
>> 734962.404654 46476.494 0.00 1150.71 141700 0 0.00
>> 0 0 0 0 1 0 0
>> 734962.404900 46476.494 0.00 1059.06 110500 0 0.00
>> 0 0 1 0 1 0 0
>> 734962.404902 46476.494 0.00 1059.06 110500 0 0.00
>> 0 0 1 1 1 1 0
>> 734962.404971 46476.495 1.70 1059.06 110500 234000
>> 1.04 0 0 1 1 1 1 0
>> ...
>>
>>
>> Best regards
>> Frieder
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