[Scilab-users] Cubic spline

Claus Futtrup cfuttrup at gmail.com
Fri Sep 9 20:34:00 CEST 2016


Hi there

In Scilab I've used interp1 to calculate a cubic spline interpolation, 
like this:

a(:,1) = interp1(log(f3),a1,log(f),'spline');

a = amplitude (magnitude). f3 is a frequency (27000 linear spaced data), 
a1 is the original data, f is the resampled 1200 frequencies 
(log-spaced), where I need the spline to interpolate some data for me.

Above should work OK, but it's not perfect, compared to a Fortran 
script. The fortran script calculates with its own cubic spline routine, 
utilizing LAPACK (DGTTRF and DGTTRS) to solve for polynomial coefficients.


The question is - above code line with the interp1 spline, which kind of 
spline is it?

Digging into interp, I see multiple options. Digging into splin, I also 
see multiple options.

I looks like the interp1 is using "natural" spline - is this correct?

It's strange because the splin help documentation doesn't recommend 
this. It says: Don't use the natural type unless the underlying function 
have zero second end points derivatives.

This might be my problem.

The Scilab help for interp1 doesn't give any examples, but does mention 
I can add an "extrap" method. Could this be any of the suggestions in 
the splin documentation. For example, could I write:

a(:,1) = interp1(log(f3),a1,log(f),'spline','not-a-knot');

?

P.S. Since not-a-knot is mentioned as the default for the splin 
function, I think it should also be made the default for interp1 ... 
just my two cents.

/Claus

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