[Scilab-users] System Identification for First order delay and dead time
Fukashiimo
noguchi.japan at gmail.com
Mon Sep 26 15:03:58 CEST 2016
Dear Denis,
Thank you for your message.
"s" is the Laplace operator and it is not a process input.
f(u)= (K/(Tau*s+1))*exp(-Td*s)*u
f(u) is the proess output and u is the process input, such as step input.
K is the constant, process gain
Tau is the constant, first order delay time constant
Td is th constant, dead time
Such case How we can get these constant values from datafit?
Could you please advise?
Thanks.
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差出人: "Denis Crété [via Scilab / Xcos - Mailing Lists Archives]" <ml-node+s994242n4034614h10 at n3.nabble.com>
宛先: "Fukashiimo" <noguchi.japan at gmail.com>
送信済み: 2016年9月25日(日曜日) 06:23:27
件名: Re: System Identification for First order delay and dead time
Hello,
If ymodel is (experimentally) proportional to u (and u is not too close to 0), it seems better to adjust z= ymodel/u = f(s).
I frequently use “datafit” for this purpose. Here f(x)= (K/(Tau*x+1))*exp(-Td*x).
HTH,
Denis
[@@ THALES GROUP INTERNAL @@]
De : users [mailto: [hidden email] ] De la part de Fukashiimo
Envoyé : samedi 24 septembre 2016 2 3:11
À : [hidden email]
Objet : Re: [Scilab-users] System Identification for First order delay and dead time
s is the Laplace operator, u is the process input vatiable, y is the process output variable,
2016/09/24 23:44 "Samuel GOUGEON [via Scilab / Xcos - Mailing Lists Archives]" < [hidden email] >:
Le 24/09/2016 15:59, Fukashiimo a écrit :
> Hello,
>
> I am looking for a Scilab software which is similar to Matlab System ID tool
> box.
>
> I would like to obtain values of parameters, Tau, K and Td for following
> first order delay + Dead time model from time series data.
> ymodel = (K/(Tau*s+1))*exp(-Td*s)*u
> ymodel: process output, u: process input
> SISO continuous time
.
What is s? What's the input variable: s or u? And is the other a known parameter?
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