[Scilab-users] numderivative Heart function

Hermes herozigle at gmail.com
Tue Dec 5 13:26:19 CET 2017


Hello;in this way we can find the extreme or critical points of the Heart
function, in Maple:
<http://mailinglists.scilab.org/file/t497622/Maple_Heart_solution.jpg>
function val = Heart(x1, x2)    
val=(1.25*x2-sqrt(abs(x1))).^2+x1.^2-1;endfunction;First function resolved
with respect to Y:function y = heart_up(x1)    y = 4/5 *
(sqrt(abs(x1))+sqrt(1-x1.^2))endfunctionfunction y = heart_down(x1)    y =
4/5 * (sqrt(abs(x1))-sqrt(1-x1.^2))endfunctionI would like to arrive at the
same solution by numerical method, Scilab!



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