[Scilab-users] filter(): How to use the last zi argument <= Re: vector operation replacing for loop

[Samuel Gougeon]

Le 12/11/2018 à 23:57, Heinz Nabielek a écrit :
> On 07.11.2018, at 20:57, Samuel Gougeon <sgougeon at free.fr> wrote:
>> Hello,
>>
>> Is there anyone here that uses to use the last filter() optional argument?
>>
>> In the example of the thread reminded below:
>> V = Z;
>> for i=2:n
>>     V(i) = a*V(i-1) + b*Z(i);
>> end
>
> In my case, a^2 + b^2 =1, if that should make any difference?

It does not.

> Has the problem been sorted out, how to use "filter"?

It hasn't been clarified. We likely must go in the code to see what it 
does... and document the option.