[Scilab-users] question on makecell

[Stéphane Mottelet]

Le 05/12/2019 à 14:25, Federico Miyara a écrit :
>
> Dear all,
>
> When using makecell such as in
>
> --> u = makecell([2 2], cos, 'hello', 1+%s^2, [1 2; 3 4])
>  u  =
>
>   [  1 fptr      ]  [1x1 string  ]
>   [1x1 polynomial]  [2x2 constant]
>
> we get a cell array where the unidimensional ordering of the cells 
> goes first along columns and then ows. However, when extracting 
> components unidimensionally, it behaves the other way around:
>
> --> u(1:4)
>  ans  =
>
>   [  1 fptr      ]
>   [1x1 polynomial]
>   [1x1 string    ]
>   [2x2 constant  ]
>
> The same happens wen applying matrix:
>
> --> matrix(u,4,1)
>  ans  =
>
>   [  1 fptr      ]
>   [1x1 polynomial]
>   [1x1 string    ]
>   [2x2 constant  ]
>
> --> matrix(u,1,4)
>  ans  =
>
>   [1 fptr]  [1x1 polynomial]  [1x1 string]  [2x2 constant]
>
> Isn't this inconsistent?
> Shouldn't makecell create the cell array going along rows and then 
> columns?

No, the doc says:

s= makecell(dims,a1,a2,...an) creates a cell array of dimensions given 
by dims with the given input arguments. The ai are stored along the last 
dimension first.


>
> Regards,
>
> Federico Miyara
>
>
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-- 
Stéphane Mottelet
Ingénieur de recherche
EA 4297 Transformations Intégrées de la Matière Renouvelable
Département Génie des Procédés Industriels
Sorbonne Universités - Université de Technologie de Compiègne
CS 60319, 60203 Compiègne cedex
Tel : +33(0)344234688
http://www.utc.fr/~mottelet

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