[Scilab-users] find name / path of open file

[Jan Åge Langeland]

Federico

Yes, I thought that would be easier. But still not as good as it could 
be, as it is difficult to use these function calls directly in 
expressions. This is the way I think it should be done in Scilab 6:

function  fp=fparts(fid)
     [a,b,fpne,d,e]=file(fid);
     [pathname,filename,extname]=fileparts(fpne);
     fp=list(fpne,pathname,filename,extname);
endfunction

fparts(fid)(1)// full path/filename.ext
fparts(fid)(2)// path
fparts(fid)(3)// filename
fparts(fid)(4)// extension

Jan

On 2019-12-27 17:00 PM, Federico Miyara wrote:
>
> Jan,
>
> Oh, thanks! That's much better than dispfiles, since it gives the name 
> as a variable. I had seen that function but somehow I didn't realize 
> that possibility.
>
> Regards,
>
> Federico Miyara
>
>
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