[Scilab-users] ipcv vs scicv

[Samuel Gougeon]

Hello Chin Luh,

Le 04/12/2020 à 01:57, Chin Luh Tan a écrit :
> Hi all,
>
> Stephane, Thanks for the quick  examples to illustrate this.
>
> Claus, as shown by Stephane, this could be now by ourselves now from 
> our own modules. Stephane has illustrated a quick demo on this, while 
> the one I was testing with is the copy of toolbox skeleton inside the 
> Scilab contrib, modified to 2 modules, installed with atoms and let it 
> load at start, results are the same.
>
> There are 2 potential issues which we should take notes:
> 1. The module which is loaded last, will have the "dominant" in the 
> base function.

Are you sure about this? This was the rule with Scilab 5, but the 
removal of the variables stack changed it within Scilab 6. I noticed 
with Scilab 6.0 that the libraries are scanned for the required function 
only after sorting their names in anti-alphabetical order.
So if both alib.myfunc() and zlib.myfunc() exist, myfunc() will call 
zlib.myfunc(), whatever is the loading order of alib and zlib.

On this respect, neither the 
https://help.scilab.org/docs/6.1.0/en_US/library.html page is 
up-to-date, not other pages dealing with libraries, like the genlib().
Here is the test:

File  =  TMPDIR+"\test\";
mkdir(File+"alib");
mkdir(File+"zlib");

code  =  [  "function test()"  ;  "disp(""test from alib"")"  ;  "endfunction"];
mputl(code,  File+"alib\test.sci");
genlib("alib",  File+"alib");

code  =  [  "function test()"  ;  "disp(""test from zlib"")"  ;  "endfunction"];
mputl(code,  File+"zlib\test.sci");
genlib("zlib",  File+"zlib");

clear  alib  zlib
load(File+"zlib\lib")
load(File+"alib\lib")

test() --> test() "test from zlib"

> for e.g.: the example that Stephane showed, we could call "lib1.foo" 
> and "lib2.foo", and calling just "foo" will be the same as  "lib2.foo".
> 2. Only macros function could be called this way, if a module has a 
> scilab gateway that called direct from Scilab, (such as scicv), you 
> could not call scicvlib.imread as the imread is directly expose from 
> the C lib to Scilab.

This is true only if the homonymous function is called without 
specifying its library. Otherwise, the name resolution works:

File  =  TMPDIR+"\test\";
mkdir(File+"alib");
code  =  [  "function cos(a)"  ;  "disp(""cos() from alib"")"  ;  "endfunction"];
mputl(code,  File+"alib\cos.sci");
genlib("alib",  File+"alib");
clear  alib
load(File+"alib\lib") cos(1)
alib.cos(1)

--> cos(1)
  ans  =
    0.5403023

--> alib.cos(1)
   "cos() from alib"

Best regards
Samuel

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