[Scilab-users] Loop query

[Lester Anderson]

This is the simplest option, based on primes(35):
[p1,p2,p3,p4,p5,p6,p7,p8,p9,p10,p11]=seq([1:$]);

Extract values based on the indices in the seq list.

On Mon, 16 Aug 2021 at 10:49, Lester Anderson <arctica1963 at gmail.com> wrote:

> Hi Samuel,
>
> Further to your method, is there a way to vectorise the list output based
> on the indices?
>
> One can access the elements as seq(1), seq(5) etc. I did look at
> list2vec(seq), but as documented this creates a single column vector.
>
> Thanks
>
> Lester
>
> On Sun, 15 Aug 2021 at 14:55, Samuel Gougeon <sgougeon at free.fr> wrote:
>
>> Le 15/08/2021 à 11:28, Lester Anderson a écrit :
>>
>> Hello Samuel,
>>
>> The size of ns (number of steps) and seq (sequence of values) are
>> variable depending on the integer input, and this seems to be one issue.
>>
>> For this reason, seq must be a list, leading to
>>
>> function [ns, seq] = collatz(p)
>>     seq = p
>>     while %T
>>         if pmodulo(p, 2)
>>             p = p*3+1
>>         else
>>             p = p/2
>>         end
>>         seq = [seq p]
>>         if p==1
>>             ns = length(seq)
>>             break
>>         end
>>     endendfunction
>> prime = primes(20);[ns, seq] = ([], list());
>> for i = 1:length(prime)
>>     [ns(i), seq(i)] = collatz(prime(i));end
>> --> ns'
>>  ans  =
>>
>>    2.   8.   6.   17.   15.   10.   13.   21.
>>
>> --> seq
>>  seq  =
>>
>>   (1) = [2,1]
>>   (2) = [3,10,5,16,8,4,2,1]
>>   (3) = [5,16,8,4,2,1]
>>   (4) = [7,22,11,34,17,52,26,13,40,20,10,5,16,8,4,2,1]
>>   (5) = [11,34,17,52,26,13,40,20,10,5,16,8,4,2,1]
>>   (6) = [13,40,20,10,5,16,8,4,2,1]
>>   (7) = [17,52,26,13,40,20,10,5,16,8,4,2,1]
>>   (8) = [19,58,29,88,44,22,11,34,17,52,26,13,40,20,10,5,16,8,4,2,1]
>>
>>
>> Samuel
>>
>>
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>
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