[Scilab-users] Getting the variable name used for a function input argument

[Jens Simon Strom]

Hi Samuel,
Your solution is quite sophisticated. To me it was confusing to call a 
function without the input being bracketed. And on top of this, that a 
variable of type /constant/ is accepted as a /string/ within the 
function. Scilab seems to be more flexible than I would dare to imagine 
before now. However it works fine. Thanks again.

Regards
Jens
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Am 05.12.2021 um 20:02 schrieb Samuel Gougeon:
> Le 04/12/2021 à 20:59, Samuel Gougeon a écrit :
>>
>> So, /unless you need to know the name *inside* printc() for some 
>> unsaid purpose/, what would be the difference between in one hand
>>
>> [name, mag, arg] = printc(myvar, "myvar")
>>
>> and on the other hand
>>
>> name = "myvar";
>> [mag, arg] = printc(myvar)
>>
>> ?
>>
>
> So, after your mail in private, you actually needs the variable's name 
> inside the function.
> Then, the easiest way to do what you expect could be to pass only the 
> name:
>
> function  printc(name)
>    execstr("c = "+name)
>    //Drucken einer komplexen Zahl mit Betrag und Winkel/°
>    mprintf([name+': %f /_%7.2f°\n'],abs(c),  180/%pi*atan(imag(c),real(c)))
> endfunction
> --> myVar = 3 - 2*%i
> myVar =
> 3. - 2.i
>
> --> printc myVar
> myVar: 3.605551 /_ -33.69°
>
> Regards
> Samuel
>
>
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