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<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff size=2>Hi
Paul,</FONT></SPAN></DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff size=2>I
usually use "find" for this kind of operation</FONT></SPAN></DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff size=2>-->
A = A (find (A ~= X))</FONT></SPAN></DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff size=2>will
remove the entry A=X from A if it is there.</FONT></SPAN></DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff size=2>I
don't know how efficient this is, but the syntax is quite
neat.</FONT></SPAN></DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff size=2>Hope
that helps.</FONT></SPAN></DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff
size=2>Mike.</FONT></SPAN></DIV>
<DIV><SPAN class=870255809-31052011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
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<DIV class=OutlookMessageHeader dir=ltr align=left><FONT face=Tahoma
size=2>-----Original Message-----<BR><B>From:</B> Carrico, Paul
[mailto:paul.carrico@esterline.com]<BR><B>Sent:</B> 31 May 2011
10:48<BR><B>To:</B> users@lists.scilab.org<BR><B>Subject:</B> [scilab-Users]
updating
matrix<BR><BR></FONT></DIV><!-- Converted from text/plain format --><BR>
<P><FONT size=2>Dear all<BR><BR>I've the following matrix :<BR><BR>A = [N1 N2
N3 .... Ni .... Nn ]' with n data<BR><BR>In an iterative process, the idea is
to decrease the size of the matrix when the wanted value(integer) is found
.<BR><BR>i = 1 -> size = n<BR>i = 2 -> the ith value is removed =>
size = n-1<BR>and so on up to n = 1<BR><BR>Is there a relevant way to do it
without creating a temporary matrix B -> copying the upper part/lower part
of the matrix -> removing A and renaming B in A ..... ?<BR><BR>The aim is
both to limit the number of iterations (and to limit the time consuming) and
to have a "clean" synthax !<BR><BR>Thanks for any
advice<BR><BR>Regards<BR><BR>Paul<BR><BR></FONT></P><PRE>--------------------------------------------------------------------------------
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