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<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2>Hi,</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff size=2>It
depends on how you want the hypermatrices to be joined. I have done this
before using "casting" to a matrix and then back again.</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff size=2>For
example if</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2>-->A = hypermat([2,3,4],[1:24])</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2>and</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2>-->B = hypermat([2,3,2],[101:112])</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff size=2>and I
want to join A and B along their common ([2,3]) direction to give a [2,3,6]
hypermatrix, then I can use</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2>-->C=[matrix(A,4,6) matrix(B,4,3)]</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2>-->D = hypermat([2,3,6],C)</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff size=2>But I
may have misunderstood what you want to do.</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2>Regards,</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2>Mike.</FONT></SPAN></DIV>
<DIV><SPAN class=796335012-01062011><FONT face=Arial color=#0000ff
size=2></FONT></SPAN> </DIV>
<BLOCKQUOTE dir=ltr style="MARGIN-RIGHT: 0px">
<DIV class=OutlookMessageHeader dir=ltr align=left><FONT face=Tahoma
size=2>-----Original Message-----<BR><B>From:</B> Adrien Vogt-Schilb
[mailto:vogt@centre-cired.fr]<BR><B>Sent:</B> 01 June 2011 13:41<BR><B>To:</B>
users@lists.scilab.org<BR><B>Subject:</B> Re: [scilab-Users] Concatenation
with hypermatrix<BR><BR></FONT></DIV>At my knowledge there's no better
way<BR><BR>Le 01/06/2011 14:33, Orbeman a écrit :
<BLOCKQUOTE cite=mid:1306931606374-3010503.post@n3.nabble.com type="cite"><PRE wrap=""> I will not use C(:,:,1)=A, C(:,:,2)=B,... but anything like
C=[C @ x] include in a loop</PRE></BLOCKQUOTE><BR><BR>
<DIV class=moz-signature>-- <BR>
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<P><B>Adrien Vogt-Schilb</B></P>
<P>Research Fellow</P>
<P><A style="COLOR: teal; TEXT-DECORATION: none"
href="mailto:vogt@centre-cired.fr" a="">vogt@centre-cired.fr</A></P>
<P>Tel: (+33) 1 43 94 73 96</P>
<P>Fax: (+33) 1 43 94 73 70</P>
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