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thank you that was it<br>
<br>
On 07/07/2011 20:54, Stephane Mottelet wrote:
<blockquote
cite="mid:20110707205435.15943l8mczvn47b4@webmail.utc.fr"
type="cite">Hello,
<br>
<br>
use the "root" parameter of ode (it is well explained in the help
page of this macro).
<br>
<br>
S.
<br>
<br>
Adrien Vogt-Schilb <a class="moz-txt-link-rfc2396E" href="mailto:vogt@centre-cired.fr"><vogt@centre-cired.fr></a> a écrit :
<br>
<br>
<blockquote type="cite">Hi everyone,
<br>
<br>
When one whishes to solve an ODE y'=f(t,y) starting at point
(t0,y0), one
<br>
can use the ode function with the following arguments ode(y0,t0,
[t0:tf], f),
<br>
where [t0:tf] is the interval on which one wants to solve the
ODE.
<br>
<br>
The terminal condition of the resolution is, in the ode
function, a time
<br>
condition (t==tf). Does anybody know if and how we can use
instead a terminal condition on y?
<br>
<br>
<br>
Let us suppose, for example, that we know that the solution
increases to
<br>
infinity (maybe in finite time). The problem is to solve the ODE
as long
<br>
as y stays under a certain value yf. We do not know which
temporal interval is to
<br>
be used to reach this yf.
<br>
<br>
Numerical example: we want to solve y'=1+a.*y^3 from y0=0 to
yf=10 for
<br>
differents values of a.
<br>
<br>
Any ideas ?
<br>
<br>
<br>
Best regards,
<br>
Adrien
<br>
<br>
AVS
<br>
<br>
<br>
</blockquote>
<br>
<br>
</blockquote>
<br>
<br>
<div class="moz-signature">-- <br>
<p style="color: teal; font-size: 12pt;"><b>Adrien Vogt-Schilb</b><br>
Research Fellow<br>
<a class="moz-txt-link-abbreviated" href="mailto:vogt@centre-cired.fr">vogt@centre-cired.fr</a><br>
Tel: (+33) 1 43 94 73 96<br>
Fax: (+33) 1 43 94 73 70<br>
</p>
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