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Hi Mike,<br>
That is exactly what I needed.<br>
Solved! Thanks!<br>
Regards<br>
Jens<br>
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<div class="moz-cite-prefix">Am 20.10.2016 13:31, schrieb Mike Page:<br>
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<div>Hi Jens,<br>
<br>
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grep does something like what you want.<br>
<br>
-->[r,w]=grep(Ms,M);<br>
-->matrix(w,size(Ms))<br>
ans =<br>
<br>
12. 4. <br>
2. 12. <br>
6. 7. <br>
<br>
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Not sure why grep produces a vector when searching for a
matrix, but it seems that way.<br>
<br>
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HTH,<br>
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Mike.<br>
<br>
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<div class="gmail_extra"><br>
<div class="gmail_quote">On 20 October 2016 at 10:32, Jens Simon
Strom <span dir="ltr"><<a moz-do-not-send="true"
href="mailto:j.s.strom@hslmg.de" target="_blank">j.s.strom@hslmg.de</a>></span>
wrote:<br>
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<pre>Hallo,
Given the string vector
M=['Jan','Feb','Mar','Apr','<wbr>May','Jun','Jul','Aug','Sep','<wbr>Oct','Nov','Dec']
which implicitly maps the string representation of the months to their number representataion I would like to map any string matrix containing elements of M into a numercal matrix showing the month numbers.
E. g.
Ms=['Dec','Apr';'Feb','Dec';'<wbr>Jun','Jul']
should be converted to
Mn=[12,4;2,12;6,7].
Ho can that be done in a vectorial style?
Backward (given Mn) it is easier to me:
<span style="color:rgb(0,0,0)">Ms</span><span style="color:rgb(92,92,92)">=</span><span style="color:rgb(50,185,185)">matrix</span><span style="color:rgb(74,85,219)">(</span><span style="color:rgb(0,0,0)">M</span><span style="color:rgb(74,85,219)">(</span><span style="color:rgb(0,0,0)">Mn</span><span style="color:rgb(74,85,219)">)</span><span style="color:rgb(0,0,0)">,</span><span style="color:rgb(50,185,185)">size</span><span style="color:rgb(74,85,219)">(</span><span style="color:rgb(0,0,0)">Mn</span><span style="color:rgb(74,85,219)">)</span><span style="color:rgb(74,85,219)">)</span>
Regards
Jens
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