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Hi,<br>
I would have also written </p>
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SumArr = [SumArr toAdd]</p>
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Why is this answer different to the original?</p>
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SumArr( (length(SumArr)+1) : (length(SumArr)+length(toAdd)) ) = toAdd;</p>
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May be im missing something, but i think in both cases you need to know the arrays in advance, dont you?</p>
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Also, i think SumArr = [SumArr toAdd] has better performance...<br>
Perhaps im not understanding the question..</p>
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<div id="x_divRplyFwdMsg" dir="ltr"><font face="Calibri, sans-serif" color="#000000" style="font-size:11pt"><b>From:</b> users <users-bounces@lists.scilab.org> on behalf of Tim Wescott <tim@wescottdesign.com><br>
<b>Sent:</b> Wednesday, March 22, 2017 8:50:26 PM<br>
<b>To:</b> Users mailing list for Scilab<br>
<b>Subject:</b> Re: [Scilab-users] add number arrays efficiently, how?</font>
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<div class="PlainText">On Thu, 2017-03-23 at 00:28 +0100, Samuel Gougeon wrote:<br>
> Le 22/03/2017 à 23:15, Erhy a écrit :<br>
> > <br>
> > Hello!<br>
> > I'm thinking in arrays - and I write<br>
> > <br>
> > SumArr = [ 1 2 3 ]; toAdd = [ 7 8 9 10 ];<br>
> > SumArr( (length(SumArr)+1) : (length(SumArr)+length(toAdd)) ) =<br>
> > toAdd;<br>
> > <br>
> > How to code it smarter?<br>
> SumArr = [SumArr toAdd]<br>
> <br>
<br>
If you know them in advance, yes. My answer was predicated on not<br>
knowing "toAdd" at the same time as the 1x3 SumArr.<br>
<br>
> -- <br>
<br>
Tim Wescott<br>
<a href="http://www.wescottdesign.com">www.wescottdesign.com</a><br>
Control & Communications systems, circuit & software design.<br>
Phone: 503.631.7815<br>
Cell: 503.349.8432<br>
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