<font size=2 face="sans-serif">not really when i do it with my pencil,
i get to the real values directly, i mean i can turn it like i want till
i get the right answers that i need, try it with lambda2?</font>
<br>
<br><font size=2 face="sans-serif">imean it could work but is it mathematical
correct?</font>
<br>
<br><font size=2 face="sans-serif">with best regards / mit freundlichen
Grüssen / cordialement</font>
<br>
<br><font size=2 face="sans-serif">Pascal Bühler<br>
Qualität-Hardware / Prüfingenieur<br>
SAUTER HeadOffice<br>
Fr. Sauter AG<br>
Im Surinam 55, CH-4016 Basel<br>
Telefon +41 (0)61 695 5646<br>
Telefax +41 (0)61 695 5619<br>
</font><a href="http://www.sauter-controls.com/"><font size=2 face="sans-serif">http://www.sauter-controls.com</font></a><font size=2 face="sans-serif"><br>
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<br><font size=1 color=#5f5f5f face="sans-serif">Von:
</font><font size=1 face="sans-serif">"Dang Ngoc Chan,
Christophe" <Christophe.Dang@sidel.com></font>
<br><font size=1 color=#5f5f5f face="sans-serif">An:
</font><font size=1 face="sans-serif">Users mailing list
for Scilab <users@lists.scilab.org>, </font>
<br><font size=1 color=#5f5f5f face="sans-serif">Datum:
</font><font size=1 face="sans-serif">27.02.2018 11:31</font>
<br><font size=1 color=#5f5f5f face="sans-serif">Betreff:
</font><font size=1 face="sans-serif">Re: [Scilab-users]
{EXT} Antwort: Re: [EXTERNAL] Problem with solving this
elegantly</font>
<br><font size=1 color=#5f5f5f face="sans-serif">Gesendet von:
</font><font size=1 face="sans-serif">"users"
<users-bounces@lists.scilab.org></font>
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<br><tt><font size=2>Hello,<br>
<br>
> De : Pascal Buehler<br>
> Envoyé : mardi 27 février 2018 11:20<br>
><br>
> Now for lambda1, insert the number to the matrix, where sigmaxx =-1,
sigmayy =5 and tauxy=4 already known is, as a stress tensor<br>
> you will get two linear equation like<br>
><br>
> -8*v1x+4*v1y=0<br>
> 4*v1x-2*v1y=0<br>
><br>
> normaly an trivial solution, but non of the sovers gave me the correct
answer?<br>
<br>
A=[-8 4 ; 4 -2]<br>
<br>
b = [0 ; 0]<br>
<br>
[x0, kerA] = linsolve(A, b)<br>
kerA =<br>
<br>
0.4472136<br>
0.8944272<br>
<br>
x0 =<br>
<br>
0.<br>
0.<br>
<br>
You notice that kerA(2)/kerA(1) = 2 which means that the result is similar
to<br>
<br>
kerA =<br>
<br>
1<br>
2<br>
<br>
x0 =<br>
<br>
0.<br>
0.<br>
<br>
Which is the excepted solution. Or?<br>
<br>
--<br>
Christophe Dang Ngoc Chan<br>
Mechanical calculation engineer<br>
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