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Hi,<br>
Thanks for all the responses and sorry for not beeing able to answer
before now.<br>
<br>
The background of my question was to write a function for formatted
output of complex variables in polar form with <br>
<pre style="font-family:Arial;font-style:normal;font-size:18.0;"><span style="color:rgb(50,185,185);">mprintf </span>like
</pre>
function printc(c)<br>
<br>
which returns the name of c on calling level, |c|, and the angle.<br>
<br>
I understand now that I have to write e. g.<br>
<br>
function printc(c,cname)<br>
<br>
where cname is the wanted string. This can even give some additional
freedeom in modifying the output name.<br>
<br>
Regards<br>
Jens<br>
<br>
<br>
<div class="moz-cite-prefix">Am 24.11.2021 um 09:51 schrieb Stéphane
Mottelet:<br>
</div>
<blockquote type="cite"
cite="mid:d2524bec-c4bd-7a40-d74b-baf5eab7edb8@utc.fr">
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<p>Hi,<br>
</p>
<div class="moz-cite-prefix">Le 24/11/2021 à 01:42, Federico
Miyara a écrit :<br>
</div>
<blockquote type="cite"
cite="mid:1250650f-0161-3eff-37ee-1ea69b625508@fceia.unr.edu.ar">
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charset=UTF-8">
<br>
<font face="Courier New">I'm not completely sure, but I think
this is not possible since what is passed to the function
isn't a variable but the value contained in the variable.</font></blockquote>
<font face="Courier New">No. Internally, input arguments are
passed as references to the true object. There is no copy unless
an input argument is modified in the function (in that case a
copy with local scope only). </font><br>
<blockquote type="cite"
cite="mid:1250650f-0161-3eff-37ee-1ea69b625508@fceia.unr.edu.ar"><font
face="Courier New"> The name is lost in the process.<br>
</font></blockquote>
<font face="Courier New">Yes, before the first line of the
function body the original object has the name of the argument,
although both names refer to the same object.</font><br>
<blockquote type="cite"
cite="mid:1250650f-0161-3eff-37ee-1ea69b625508@fceia.unr.edu.ar"><font
face="Courier New"> <br>
An alternative way (but I don't know if this would be
acceptable for you) is that the function had as its argument a
variable name (hence, a string), so your x would be "xNum",
instead of 123. Then you could use evstr() to get the value of
the variable to proceed with the processing.<br>
</font></blockquote>
<p><font face="Courier New">I think that we are in the presence of
an XY problem (<a class="moz-txt-link-freetext"
href="https://xyproblem.info/" moz-do-not-send="true">https://xyproblem.info/</a>)
and that Jens should explain the whole story.</font></p>
<p><font face="Courier New">S.<br>
</font></p>
<blockquote type="cite"
cite="mid:1250650f-0161-3eff-37ee-1ea69b625508@fceia.unr.edu.ar"><font
face="Courier New"> <br>
Regards,<br>
<br>
Federico Miyara<br>
<br>
</font><br>
<div class="moz-cite-prefix">On 23/11/2021 17:18, Jens Simon
Strom wrote:<br>
</div>
<blockquote type="cite"
cite="mid:740fb2a0-d406-6aa5-b02c-0fd2fcb9bf49@hslmg.de"> <br>
Hi Scilab friends, <br>
Given a numeric variable like xNum as an input argument of a
function call, how can I produce the variable name string
"xNum" within the function? <br>
<br>
Example: <br>
<br>
function [name,y]=foo(x) <br>
name=??? <br>
y=x^2 <br>
endfunction <br>
<br>
xNum=123. <br>
[name,y]=foo(xNum) <br>
The result for name should be the string "xNum" <br>
<br>
Regards <br>
Jens <br>
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<pre class="moz-signature" cols="72">--
Stéphane Mottelet
Ingénieur de recherche
EA 4297 Transformations Intégrées de la Matière Renouvelable
Département Génie des Procédés Industriels
Sorbonne Universités - Université de Technologie de Compiègne
CS 60319, 60203 Compiègne cedex
Tel : +33(0)344234688
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