[scilab-Users] Trouble with the function parser

[Vincent COUVERT]

Hi,

It's a Scilab parser bug. You can work around it by defining your 
function on one line only:
for k = 1:21
  function [x,y]=myfct2(a,b);x=a+b;y=a-b;endfunction
  [u,v] = myfct2(k, k+1)
end

Could you please report this bug in Bugzilla database ?

Vincent

PS :
 - you do not need to use "do" in a for loop definition
 - your loop redefines the function myfct2 for every k value





Teodor Calin a écrit :
> Okay, here's my  complaint:
>
>
> I write this code:
> "
> clear;
>  
> function [x,y]=myfct(a,b)
> x=a+b
> y=a-b
> endfunction
>
> [x,y]=myfct(3,2)
>
> //////////////////////////////////
>
> for k = 1:21 do
>
>   function [x,y]=myfct2(a,b)
>       x=a+b
>       y=a-b
>   endfunction
>
>   [u,v] = myfct2(k, k+1)
>  
> end
> "
>
> And I get this result:
> "
> y  =
>
>     1.
>  x  =
>
>     5.
> =a-b
>  !--error 2
> invalid factor
> at line       3 of function myfct2 called by :
>   endfunction
> line    20 of exec file called by :
> exec("S:/Depannage.sci");
> in  execstr instruction    called by :
> "
>
> In other words, defining functions with more than one return variables 
> inside loops
> does not work.
> By the way, what (in the *#!§^$) does 'invalid factor' mean ?
>
>
> Also, I'm really mad about this, because if I write
>
> "
> for k = 1:21 do
>
>   function y=myfct3(a,b)
>       y=a-b
>   endfunction
>
>   u = myfct3(k, k+1)
>  
> end
> "
>
> this works perfectly well. So I expected it to work for the above too !
>
> So, is there a way to circumvent this ?
>
> Thanks in advance
>
> Teodor
>
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-- 
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Vincent COUVERT
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