non-square root function?

Huub van Niekerk huubvanniekerk at gmail.com
Wed Jan 14 10:55:10 CET 2009


On Wed, 14 Jan 2009 09:47:29 +0000, Francis Drossaert wrote:

> Uhm that is basics math problem and there is no special function for it
> (as far I know):
> 
> sqrt(4) = 4^(1/2) = 2
> 3root(8) = 8^(1/3) = 2
> 4root(16) = 16^(1/4) = 2
> 
>

Yes, it is basic math. But since the sqrt function is there as well... 
I'll use the ^ then.




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