[scilab-Users] Re: non-square root function?

[Francis Drossaert]

I understand but just like there are infinite powers there are infinite roots and to give them all separate functions is impossible. If you like to use a function (which sqrt actually is) for aesthetic reasons than why not write your own. 

-----Original Message-----
From: news [mailto:news at ger.gmane.org] On Behalf Of Huub van Niekerk
Sent: 14 January 2009 09:55
To: users at lists.scilab.org
Subject: [scilab-Users] Re: non-square root function?

On Wed, 14 Jan 2009 09:47:29 +0000, Francis Drossaert wrote:

> Uhm that is basics math problem and there is no special function for it
> (as far I know):
> 
> sqrt(4) = 4^(1/2) = 2
> 3root(8) = 8^(1/3) = 2
> 4root(16) = 16^(1/4) = 2
> 
>

Yes, it is basic math. But since the sqrt function is there as well... 
I'll use the ^ then.


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