[scilab-Users] Re: format(): limit of the number of digits

[Adrien Vogt-Schilb]

Hi

I am not sure, but maybe this toolbo may help
http://atoms.scilab.org/toolboxes/mpscilab

It says it is for arbitrary precision calculus.


On 01/03/2012 13:09, Mike Page wrote:
> Hi Jonas,
>
> I don't think you can do that.  The longest native integer type is (AFAIK)
> 32 bits.  This will only hold about 9 decimal digits.  So the result of
> factorial 24 in integer form would be an overflow.
>
> -->i=int32(factorial(24))
>   i  =
>
>   -2147483648
>
> while
> -->i=int32(factorial(12))
>   i  =
>
>    479001600
> works correctly and is the limit of how far you can get with an integer
> type.
>
> As I mentioned before, the only way I know to go beyond these limits is to
> do your own arithmetic with a structured type holding the extended words of
> the data.  If your arithmetic is complicated, then this would be hard.
> Maybe Scilab is not the best tool for your purposes?  You can find some
> information about this problem in Wikipedia
> (http://en.wikipedia.org/wiki/Arbitrary-precision_arithmetic).
>
> HTH
> Mike.
>
>
> -----Original Message-----
> From: jonas [mailto:jonathanattia at gmail.com]
> Sent: 01 March 2012 11:50
> To: users at lists.scilab.org
> Subject: [scilab-Users] Re: format(): limit of the number of digits
>
>
> Thank you for your post.
>
> This syntax/function is valid for a floating-point number.
> How can I get a high number of digits for a positive integer?
>
> Here's a numerical example: factorial(24) = 6.204484017332394100D+23
>
> Thank you in advance.
>
> Best regards,
> Jonas.
>
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