[scilab-Users] Re: format(): limit of the number of digits

[Adrien Vogt-Schilb]

There are also
http://atoms.scilab.org/toolboxes/dbldbl   : for double double 
precision, maintained by a member of the scilab team, and

http://atoms.scilab.org/toolboxes/DD_QD which says it goes as far as 
quadruple double precision.

Hope one of these helps

On 01/03/2012 14:40, Adrien Vogt-Schilb wrote:
> Hi
>
> I am not sure, but maybe this toolbo may help
> http://atoms.scilab.org/toolboxes/mpscilab
>
> It says it is for arbitrary precision calculus.
>
>
> On 01/03/2012 13:09, Mike Page wrote:
>> Hi Jonas,
>>
>> I don't think you can do that.  The longest native integer type is (AFAIK)
>> 32 bits.  This will only hold about 9 decimal digits.  So the result of
>> factorial 24 in integer form would be an overflow.
>>
>> -->i=int32(factorial(24))
>>   i  =
>>
>>   -2147483648
>>
>> while
>> -->i=int32(factorial(12))
>>   i  =
>>
>>    479001600
>> works correctly and is the limit of how far you can get with an integer
>> type.
>>
>> As I mentioned before, the only way I know to go beyond these limits is to
>> do your own arithmetic with a structured type holding the extended words of
>> the data.  If your arithmetic is complicated, then this would be hard.
>> Maybe Scilab is not the best tool for your purposes?  You can find some
>> information about this problem in Wikipedia
>> (http://en.wikipedia.org/wiki/Arbitrary-precision_arithmetic).
>>
>> HTH
>> Mike.
>>
>>
>> -----Original Message-----
>> From: jonas [mailto:jonathanattia at gmail.com]
>> Sent: 01 March 2012 11:50
>> To:users at lists.scilab.org
>> Subject: [scilab-Users] Re: format(): limit of the number of digits
>>
>>
>> Thank you for your post.
>>
>> This syntax/function is valid for a floating-point number.
>> How can I get a high number of digits for a positive integer?
>>
>> Here's a numerical example: factorial(24) = 6.204484017332394100D+23
>>
>> Thank you in advance.
>>
>> Best regards,
>> Jonas.
>>
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>> 0p3790178.html
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>> Nabble.com.
>>
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