[Scilab-users] Finding elements occurring once in a matrix

[Rafael Guerra]

Try the following, without loops, inspired by a solution by B. Mohandes :

--> x = [1.1 1.1 3.2; 2.3 1.1 1.1; 4.7 5.2 5.2]
 x  = 
   1.1   1.1   3.2
   2.3   1.1   1.1
   4.7   5.2   5.2

--> y = unique(x); y0 = [min(y)-1; y]; y(find(histc(y0,x(:),%F)==1))
 ans  =
   2.3
   3.2
   4.7

Regards,
Rafael

-----Original Message-----
From: users <users-bounces at lists.scilab.org> On Behalf Of Stéphane Mottelet
Sent: Friday, July 5, 2019 7:24 PM
To: users at lists.scilab.org
Subject: Re: [Scilab-users] Finding elements occuring once in a matrix

Hello,

Maybe not optimal, but does the job:

x = [1 1 3
2 1 1
4 5 5];

f = [];
for y=unique(x(:))'
   if length(find(x==y)) == 1
    f = [f y];
   end
end

--> f
  f  =

    2.   3.   4.

S.

Le 05/07/2019 à 18:03, Izabela Wójcik-Grząba a écrit :
> Hello,
>
> Is there a simple way of finding elements of matrix which occurs only 
> once. For example in this matrix it would be 3 and 4:
> [1 1 3
> 2 1 1
> 4 5 5]
>
> For the time being I couldn't find any smart idea for that. Could you 
> help?
>
> Kind regards,
> Iza

-- 
Stéphane Mottelet
Ingénieur de recherche
EA 4297 Transformations Intégrées de la Matière Renouvelable
Département Génie des Procédés Industriels
Sorbonne Universités - Université de Technologie de Compiègne
CS 60319, 60203 Compiègne cedex
Tel : +33(0)344234688
http://www.utc.fr/~mottelet