[Scilab-users] Finding elements occurring once in a matrix
Izabela Wójcik-Grząba
iwoj at il.pw.edu.pl
Fri Jul 5 21:01:06 CEST 2019
Raphael, Stephane,
Thanks a lot for your quick reaction and help.
Best regards,
Iza
W dniu 05.07.2019 20:23, Rafael Guerra napisał(a):
> Try the following, without loops, inspired by a solution by B. Mohandes
> :
>
> --> x = [1.1 1.1 3.2; 2.3 1.1 1.1; 4.7 5.2 5.2]
> x =
> 1.1 1.1 3.2
> 2.3 1.1 1.1
> 4.7 5.2 5.2
>
> --> y = unique(x); y0 = [min(y)-1; y]; y(find(histc(y0,x(:),%F)==1))
> ans =
> 2.3
> 3.2
> 4.7
>
> Regards,
> Rafael
>
> -----Original Message-----
> From: users <users-bounces at lists.scilab.org> On Behalf Of Stéphane
> Mottelet
> Sent: Friday, July 5, 2019 7:24 PM
> To: users at lists.scilab.org
> Subject: Re: [Scilab-users] Finding elements occuring once in a matrix
>
> Hello,
>
> Maybe not optimal, but does the job:
>
> x = [1 1 3
> 2 1 1
> 4 5 5];
>
> f = [];
> for y=unique(x(:))'
> if length(find(x==y)) == 1
> f = [f y];
> end
> end
>
> --> f
> f =
>
> 2. 3. 4.
>
> S.
>
> Le 05/07/2019 à 18:03, Izabela Wójcik-Grząba a écrit :
>> Hello,
>>
>> Is there a simple way of finding elements of matrix which occurs only
>> once. For example in this matrix it would be 3 and 4:
>> [1 1 3
>> 2 1 1
>> 4 5 5]
>>
>> For the time being I couldn't find any smart idea for that. Could you
>> help?
>>
>> Kind regards,
>> Iza
More information about the users
mailing list