[Scilab-users] Reimann Zeta function

[Claus Futtrup]

Hi Lester

Please be reminded of the correct spelling : Riemann

Cheers,
Claus

On 29-11-2021 18:23, Lester Anderson wrote:
> Hi all,
>
> Found a bit of Matlab/Octave code to solve the Reimann Zeta function 
> for values >= 0, not perfect but it's a start. Need to figure out how 
> to deal with negative values.
>
> Lester
>
> // Reimann Zeta function: valid for t >= 0
>
> function  f=F(x)
>      f  =  1./(gamma(t(j))).*x.^(t(j)-1)./(exp(x)-1);
> endfunction
>
> function  [z]=zeta(t)
>      global  x
>    z  =  zeros(size(t));
>    for  j  =  1:prod(size(t))
>      if(real(t(j))  >=  0)
>        if(imag(t(j))  ==  0  &&  real(t(j))  >  1)
>          z(j)  =  intg(0,200,F)
>        elseif(t(j)  ==  0)
>          z(j)  =  -0.5;
>        elseif(t(j)  ==  1)
>          z(j)  =  %inf;
>        else
>          for  k  =  1:1:100
>            z(j)  =  (-1).^(k-1)./(k.^t(j));
>          end
>          z(j)  =  1./(1-2.^(1-t(j))).*z(j);
>        end
>      else
>        z(j)  =  2.^t(j).*%pi.^(t(j)-1).*sin(%pi.*t(j)./2).*gamma(1-t(j)).*zeta(1-t(j));
>    end
> end
>
> endfunction
>
> On Mon, 29 Nov 2021 at 08:51, Heinz Nabielek <heinznabielek at me.com> wrote:
>
>     Riemann zeta function !
>
>     Georg Friedrich Bernhard Riemann (17 September 1826 – 20 July
>     1866) was a German mathematician who made contributions to
>     analysis, number theory, and differential geometry.
>
>     Heinz
>
>
>
>     > On 29.11.2021, at 09:39, Lester Anderson <arctica1963 at gmail.com>
>     wrote:
>     >
>     > Hello all,
>     >
>     > I am interested in the Reimann Zeta function, but it does not
>     appear as an option directly with Scilab (v6.1.1).
>     >
>     > Has anyone already prepared a function for this?
>     >
>     > Lester
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>
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