[Scilab-users] Reimann Zeta function
Heinz Nabielek
heinznabielek at me.com
Mon Nov 29 18:35:39 CET 2021
Riemann !!! Do not mutilate names....
> On 29.11.2021, at 18:23, Lester Anderson <arctica1963 at gmail.com> wrote:
>
> Hi all,
>
> Found a bit of Matlab/Octave code to solve the Reimann Zeta function for values >= 0, not perfect but it's a start. Need to figure out how to deal with negative values.
>
> Lester
>
> // Reimann Zeta function: valid for t >= 0
>
>
>
> function f=F(x)
>
>
> f = 1./(gamma(t(j))).*x.^(t(j)-1)./(exp(x)-1);
> endfunction
>
>
>
> function [z]=zeta(t)
>
>
> global x
>
>
> z = zeros(size(t));
>
>
> for j = 1:prod(size(t))
>
>
> if(real(t(j)) >= 0)
>
>
> if(imag(t(j)) == 0 && real(t(j)) > 1)
>
>
> z(j) = intg(0,200,F)
>
>
> elseif(t(j) == 0)
>
>
> z(j) = -0.5;
>
>
> elseif(t(j) == 1)
>
>
> z(j) = %inf;
>
>
> else
>
>
> for k = 1:1:100
>
>
> z(j) = (-1).^(k-1)./(k.^t(j));
>
>
> end
>
>
> z(j) = 1./(1-2.^(1-t(j))).*z(j);
>
>
> end
>
>
> else
>
>
> z(j) = 2.^t(j).*%pi.^(t(j)-1).*sin(%pi.*t(j)./2).*gamma(1-t(j)).*zeta(1-t(j));
>
>
> end
> end
>
>
>
> endfunction
>
>
> On Mon, 29 Nov 2021 at 08:51, Heinz Nabielek <heinznabielek at me.com> wrote:
> Riemann zeta function !
>
> Georg Friedrich Bernhard Riemann (17 September 1826 – 20 July 1866) was a German mathematician who made contributions to analysis, number theory, and differential geometry.
>
> Heinz
>
>
>
> > On 29.11.2021, at 09:39, Lester Anderson <arctica1963 at gmail.com> wrote:
> >
> > Hello all,
> >
> > I am interested in the Reimann Zeta function, but it does not appear as an option directly with Scilab (v6.1.1).
> >
> > Has anyone already prepared a function for this?
> >
> > Lester
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