[Scilab-users] please help, I have just a mental blockade

[Federico Miyara]

Heinz,

It isn't clear what you need, I don't underastand the relationship 
between EE and E.

Except for the first 0 in E, it seems that each consecutive number n is 
repeated n+1 times up to the number indicated by the first component of 
EE. Is this what you are looking for?

This is a simple (though not very efficient) way of attaining that:

m = EE(1);
E = []; //or E = 0 if the first 0 is really needed
for k=0:m
    E = [E, k*ones(1, k+1)];
end

Regards.

Federico Miyara

On 07/02/2022 14:35, Heinz Nabielek wrote:
> Sorry, colleagues  -   please help, I have just a mental blockade.
>
> Given vector EE= [3 5 8]
>
> I want to create a stepwise increasing vector E= [0 0 1 1 2 2 2 3 3 3 3]
>
> And would need a system that works for much larger numbers....
>
> Probably dead easy?
> Heinz
>
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